2x^2+40.5x-388=0

Solution for 2x^2+40.5x-388=0 equation:

2x^2+40.5x-388=0

a = 2; b = 40.5; c = -388;
Δ = b2-4ac
Δ = 40.52-4·2·(-388)
Δ = 4744.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40.5)-\sqrt{4744.25}}{2*2}=\frac{-40.5-\sqrt{4744.25}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40.5)+\sqrt{4744.25}}{2*2}=\frac{-40.5+\sqrt{4744.25}}{4}
$